Solve 1=x^2y+2x

$$1 = x ^ { 2 } y + 2 x$$

Solve for y

$$y=\frac{1-2x}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$x^{2}y+2x=1$$

Subtract 2x from both sides.

$$x^{2}y=1-2x$$

Divide both sides by x^{2}.

$$\frac{x^{2}y}{x^{2}}=\frac{1-2x}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$y=\frac{1-2x}{x^{2}}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{\sqrt{y+1}+1}{y}\text{; }x=\frac{\sqrt{y+1}-1}{y}\text{, }&y\neq 0\\x=\frac{1}{2}=0.5\text{, }&y=0\end{matrix}\right.$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{\sqrt{y+1}+1}{y}\text{; }x=\frac{\sqrt{y+1}-1}{y}\text{, }&y\neq 0\text{ and }y\geq -1\\x=\frac{1}{2}=0.5\text{, }&y=0\end{matrix}\right.$$