Solve 1:y=x+3

$$1 : y = x + 3$$

Solve for x

$$x=-3+\frac{1}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by y.

$$1=yx+y\times 3$$

Swap sides so that all variable terms are on the left hand side.

$$yx+y\times 3=1$$

Subtract y\times 3 from both sides.

$$yx=1-y\times 3$$

Multiply -1 and 3 to get -3.

$$yx=1-3y$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{1-3y}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{1-3y}{y}$$

Divide -3y+1 by y.

$$x=-3+\frac{1}{y}$$

Solve for y

$$y=\frac{1}{x+3}$$

$$x\neq -3$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.

$$1=yx+y\times 3$$

Swap sides so that all variable terms are on the left hand side.

$$yx+y\times 3=1$$

Combine all terms containing y.

$$\left(x+3\right)y=1$$

Divide both sides by x+3.

$$\frac{\left(x+3\right)y}{x+3}=\frac{1}{x+3}$$

Dividing by x+3 undoes the multiplication by x+3.

$$y=\frac{1}{x+3}$$

Variable y cannot be equal to 0.

$$y=\frac{1}{x+3}\text{, }y\neq 0$$