Solve 1+6div(3*2)^2+1-1

$$1 + 6 \div ( 3 \times 2 ) ^ { 2 } + 1 - 1$$

Evaluate

$$\frac{7}{6}\approx 1.166666667$$

Solution Steps

Multiply 3 and 2 to get 6.

$$1+\frac{6}{6^{2}}+1-1$$

Calculate 6 to the power of 2 and get 36.

$$1+\frac{6}{36}+1-1$$

Reduce the fraction \frac{6}{36} to lowest terms by extracting and canceling out 6.

$$1+\frac{1}{6}+1-1$$

Add 1 and \frac{1}{6} to get \frac{7}{6}.

$$\frac{7}{6}+1-1$$

Add \frac{7}{6} and 1 to get \frac{13}{6}.

$$\frac{13}{6}-1$$

Subtract 1 from \frac{13}{6} to get \frac{7}{6}.

$$\frac{7}{6}$$

Factor

$$\frac{7}{2 \cdot 3} = 1\frac{1}{6} = 1.1666666666666667$$