Solve 1+4+uv/2uu-2

$$1 + 4 + \frac { u v } { 2 u u } - 2$$

Evaluate

$$\frac{v}{2u}+3$$

Short Solution Steps

Multiply u and u to get u^{2}.

$$1+4+\frac{uv}{2u^{2}}-2$$

Add 1 and 4 to get 5.

$$5+\frac{uv}{2u^{2}}-2$$

Cancel out u in both numerator and denominator.

$$5+\frac{v}{2u}-2$$

Subtract 2 from 5 to get 3.

$$3+\frac{v}{2u}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{2u}{2u}.

$$\frac{3\times 2u}{2u}+\frac{v}{2u}$$

Since \frac{3\times 2u}{2u} and \frac{v}{2u} have the same denominator, add them by adding their numerators.

$$\frac{3\times 2u+v}{2u}$$

Do the multiplications in 3\times 2u+v.

$$\frac{6u+v}{2u}$$

Factor

$$\frac{6u+v}{2u}$$