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\frac{9+6b+b^{2}}{9}
Factor out \frac{1}{9}.
\left(b+3\right)^{2}
Consider 9+6b+b^{2}. Use the perfect square formula, p^{2}+2pq+q^{2}=\left(p+q\right)^{2}, where p=b and q=3.
\frac{\left(b+3\right)^{2}}{9}
Rewrite the complete factored expression.