Solve 07x^2-9x

$$07 x ^ { 2 } - 9 x$$

Evaluate

$$-9x$$

Solution Steps

Multiply 0 and 7 to get 0.

$$0x^{2}-9x$$

Anything times zero gives zero.

$$0-9x$$

Anything plus zero gives itself.

$$-9x$$

Differentiate w.r.t. x

$$-9$$

Steps Using Definition of a Derivative

Multiply 0 and 7 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0x^{2}-9x)$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0-9x)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-9x)$$

The derivative of ax^{n} is nax^{n-1}.

$$-9x^{1-1}$$

Subtract 1 from 1.

$$-9x^{0}$$

For any term t except 0, t^{0}=1.

$$-9$$