Solve 03x-7<26x+15

$$03 x - 7 < 26 x + 15$$

Solve for x

$$x>-\frac{11}{13}$$

Solution Steps

Multiply 0 and 3 to get 0.

$$0x-7<26x+15$$

Anything times zero gives zero.

$$0-7<26x+15$$

Subtract 7 from 0 to get -7.

$$-7<26x+15$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$26x+15>-7$$

Subtract 15 from both sides.

$$26x>-7-15$$

Subtract 15 from -7 to get -22.

$$26x>-22$$

Divide both sides by 26. Since 26 is positive, the inequality direction remains the same.

$$x>\frac{-22}{26}$$

Reduce the fraction \frac{-22}{26} to lowest terms by extracting and canceling out 2.

$$x>-\frac{11}{13}$$