Solve 03x^2+x-06x^2-04x

$$03 x ^ { 2 } + x - 06 x ^ { 2 } - 04 x$$

Evaluate

$$x$$

Solution Steps

Multiply 0 and 3 to get 0.

$$0x^{2}+x-0\times 6x^{2}-0\times 4x$$

Anything times zero gives zero.

$$0+x-0\times 6x^{2}-0\times 4x$$

Anything plus zero gives itself.

$$x-0\times 6x^{2}-0\times 4x$$

Multiply 0 and 6 to get 0.

$$x-0x^{2}-0\times 4x$$

Anything times zero gives zero.

$$x-0-0\times 4x$$

Multiply 0 and 4 to get 0.

$$x-0-0x$$

Anything times zero gives zero.

$$x-0-0$$

Multiply -1 and 0 to get 0.

$$x+0-0$$

Anything plus zero gives itself.

$$x-0$$

Multiply -1 and 0 to get 0.

$$x+0$$

Anything plus zero gives itself.

$$x$$

Differentiate w.r.t. x

$$1$$

Steps Using Definition of a Derivative

Multiply 0 and 3 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0x^{2}+x-0\times 6x^{2}-0\times 4x)$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0+x-0\times 6x^{2}-0\times 4x)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-0\times 6x^{2}-0\times 4x)$$

Multiply 0 and 6 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-0x^{2}-0\times 4x)$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-0-0\times 4x)$$

Multiply 0 and 4 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-0-0x)$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-0-0)$$

Multiply -1 and 0 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+0-0)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-0)$$

Multiply -1 and 0 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+0)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x)$$

The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$