Solve 025k+15-k-35

$$025 k + 15 - k - 35$$

Evaluate

$$-k-20$$

Solution Steps

Multiply 0 and 25 to get 0.

$$0k+15-k-35$$

Anything times zero gives zero.

$$0+15-k-35$$

Add 0 and 15 to get 15.

$$15-k-35$$

Subtract 35 from 15 to get -20.

$$-20-k$$

Differentiate w.r.t. k

$$-1$$

Steps Using Derivative Rule for Sum

Multiply 0 and 25 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}k}(0k+15-k-35)$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}k}(0+15-k-35)$$

Add 0 and 15 to get 15.

$$\frac{\mathrm{d}}{\mathrm{d}k}(15-k-35)$$

Subtract 35 from 15 to get -20.

$$\frac{\mathrm{d}}{\mathrm{d}k}(-20-k)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-k^{1-1}$$

Subtract 1 from 1.

$$-k^{0}$$

For any term t except 0, t^{0}=1.

$$-1$$