Solve 02x>0.3x+1

$$02 x > 0.3 x + 1$$

Solve for x

$$x<-\frac{10}{3}$$

Solution Steps

Multiply 0 and 2 to get 0.

$$0x>0.3x+1$$

Anything times zero gives zero.

$$0>0.3x+1$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$0.3x+1<0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$0.3x<-1$$

Divide both sides by 0.3. Since 0.3 is positive, the inequality direction remains the same.

$$x<\frac{-1}{0.3}$$

Expand \frac{-1}{0.3} by multiplying both numerator and the denominator by 10.

$$x<\frac{-10}{3}$$

Fraction \frac{-10}{3} can be rewritten as -\frac{10}{3} by extracting the negative sign.

$$x<-\frac{10}{3}$$