Solve 002t^4-3192t^3+432t^2

$$002 { t }^{ 4 } -3192 { t }^{ 3 } +432 { t }^{ 2 }$$

Evaluate

$$24\left(18-133t\right)t^{2}$$

Solution Steps

Multiply 0 and 0 to get 0.

$$0\times 2t^{4}-3192t^{3}+432t^{2}$$

Multiply 0 and 2 to get 0.

$$0t^{4}-3192t^{3}+432t^{2}$$

Anything times zero gives zero.

$$0-3192t^{3}+432t^{2}$$

Anything plus zero gives itself.

$$-3192t^{3}+432t^{2}$$

Factor

$$24\left(18-133t\right)t^{2}$$

Solution Steps

Factor out 24.

$$24\left(0-133t^{3}+18t^{2}\right)$$

Consider -133t^{3}+18t^{2}. Factor out t^{2}.

$$t^{2}\left(-133t+18\right)$$

Rewrite the complete factored expression.

$$24t^{2}\left(-133t+18\right)$$