Solve 0.8x-2-5+xleq4x/3+2

$$0.8x-2-5+x \leq \frac{ 4x }{ 3 } +2$$

Solve for x

$$x\leq \frac{135}{7}$$

Solution Steps

Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.

$$2.4x-6-15+3x\leq 4x+6$$

Subtract 15 from -6 to get -21.

$$2.4x-21+3x\leq 4x+6$$

Combine 2.4x and 3x to get 5.4x.

$$5.4x-21\leq 4x+6$$

Subtract 4x from both sides.

$$5.4x-21-4x\leq 6$$

Combine 5.4x and -4x to get 1.4x.

$$1.4x-21\leq 6$$

Add 21 to both sides.

$$1.4x\leq 6+21$$

Add 6 and 21 to get 27.

$$1.4x\leq 27$$

Divide both sides by 1.4. Since 1.4 is positive, the inequality direction remains the same.

$$x\leq \frac{27}{1.4}$$

Expand \frac{27}{1.4} by multiplying both numerator and the denominator by 10.

$$x\leq \frac{270}{14}$$

Reduce the fraction \frac{270}{14} to lowest terms by extracting and canceling out 2.

$$x\leq \frac{135}{7}$$