Solve 0.8*(7-4div(2/15+2/3))

$$0.8 \times (7-4 \div ( \frac{ 2 }{ 15 } + \frac{ 2 }{ 3 } ))$$

Evaluate

$$1.6$$

Solution Steps

Least common multiple of 15 and 3 is 15. Convert \frac{2}{15} and \frac{2}{3} to fractions with denominator 15.

$$0.8\left(7-\frac{4}{\frac{2}{15}+\frac{10}{15}}\right)$$

Since \frac{2}{15} and \frac{10}{15} have the same denominator, add them by adding their numerators.

$$0.8\left(7-\frac{4}{\frac{2+10}{15}}\right)$$

Add 2 and 10 to get 12.

$$0.8\left(7-\frac{4}{\frac{12}{15}}\right)$$

Reduce the fraction \frac{12}{15} to lowest terms by extracting and canceling out 3.

$$0.8\left(7-\frac{4}{\frac{4}{5}}\right)$$

Divide 4 by \frac{4}{5} by multiplying 4 by the reciprocal of \frac{4}{5}.

$$0.8\left(7-4\times \frac{5}{4}\right)$$

Cancel out 4 and 4.

$$0.8\left(7-5\right)$$

Subtract 5 from 7 to get 2.

$$0.8\times 2$$

Multiply 0.8 and 2 to get 1.6.

$$1.6$$

Factor

$$\frac{2 ^ {3}}{5} = 1\frac{3}{5} = 1.6$$