Solve for T_1
T_{1}=-\frac{4T_{2}}{3}+115
Solve for T_2
T_{2}=\frac{345-3T_{1}}{4}
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0.6T_{1}=69-0.8T_{2}
Subtract 0.8T_{2} from both sides.
0.6T_{1}=-\frac{4T_{2}}{5}+69
The equation is in standard form.
\frac{0.6T_{1}}{0.6}=\frac{-\frac{4T_{2}}{5}+69}{0.6}
Divide both sides of the equation by 0.6, which is the same as multiplying both sides by the reciprocal of the fraction.
T_{1}=\frac{-\frac{4T_{2}}{5}+69}{0.6}
Dividing by 0.6 undoes the multiplication by 0.6.
T_{1}=-\frac{4T_{2}}{3}+115
Divide 69-\frac{4T_{2}}{5} by 0.6 by multiplying 69-\frac{4T_{2}}{5} by the reciprocal of 0.6.
0.8T_{2}=69-0.6T_{1}
Subtract 0.6T_{1} from both sides.
0.8T_{2}=-\frac{3T_{1}}{5}+69
The equation is in standard form.
\frac{0.8T_{2}}{0.8}=\frac{-\frac{3T_{1}}{5}+69}{0.8}
Divide both sides of the equation by 0.8, which is the same as multiplying both sides by the reciprocal of the fraction.
T_{2}=\frac{-\frac{3T_{1}}{5}+69}{0.8}
Dividing by 0.8 undoes the multiplication by 0.8.
T_{2}=\frac{345-3T_{1}}{4}
Divide 69-\frac{3T_{1}}{5} by 0.8 by multiplying 69-\frac{3T_{1}}{5} by the reciprocal of 0.8.
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