Solve 0.4(9)^2+17(9)-291+2200/9

$$0.4 ( 9 ) ^ { 2 } + 17 ( 9 ) - 291 + \frac { 2200 } { 9 }$$

Evaluate

$$\frac{6248}{45}\approx 138.844444444$$

Solution Steps

Calculate 9 to the power of 2 and get 81.

$$0.4\times 81+17\times 9-291+\frac{2200}{9}$$

Multiply 0.4 and 81 to get 32.4.

$$32.4+17\times 9-291+\frac{2200}{9}$$

Multiply 17 and 9 to get 153.

$$32.4+153-291+\frac{2200}{9}$$

Add 32.4 and 153 to get 185.4.

$$185.4-291+\frac{2200}{9}$$

Subtract 291 from 185.4 to get -105.6.

$$-105.6+\frac{2200}{9}$$

Convert decimal number -105.6 to fraction -\frac{1056}{10}. Reduce the fraction -\frac{1056}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{528}{5}+\frac{2200}{9}$$

Least common multiple of 5 and 9 is 45. Convert -\frac{528}{5} and \frac{2200}{9} to fractions with denominator 45.

$$-\frac{4752}{45}+\frac{11000}{45}$$

Since -\frac{4752}{45} and \frac{11000}{45} have the same denominator, add them by adding their numerators.

$$\frac{-4752+11000}{45}$$

Add -4752 and 11000 to get 6248.

$$\frac{6248}{45}$$

Factor

$$\frac{11 \cdot 71 \cdot 2 ^ {3}}{5 \cdot 3 ^ {2}} = 138\frac{38}{45} = 138.84444444444443$$