Solve 0.25*(-2)^3-[4div(-2/3)^2+1]

$$0.25 \times ( - 2 ) ^ { 3 } - [ 4 \div ( - \frac { 2 } { 3 } ) ^ { 2 } + 1 ]$$

Evaluate

$$-12$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$0.25\left(-8\right)-\left(\frac{4}{\left(-\frac{2}{3}\right)^{2}}+1\right)$$

Multiply 0.25 and -8 to get -2.

$$-2-\left(\frac{4}{\left(-\frac{2}{3}\right)^{2}}+1\right)$$

Calculate -\frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-2-\left(\frac{4}{\frac{4}{9}}+1\right)$$

Divide 4 by \frac{4}{9} by multiplying 4 by the reciprocal of \frac{4}{9}.

$$-2-\left(4\times \frac{9}{4}+1\right)$$

Cancel out 4 and 4.

$$-2-\left(9+1\right)$$

Add 9 and 1 to get 10.

$$-2-10$$

Subtract 10 from -2 to get -12.

$$-12$$

Factor

$$-12$$