Solve 0.25*(-2)^-2div16^-1-(pi-3)^0

$$0.25 \times ( - 2 ) ^ { - 2 } \div 16 ^ { - 1 } - ( \pi - 3 ) ^ { 0 }$$

Evaluate

$$0$$

Solution Steps

Calculate -2 to the power of -2 and get \frac{1}{4}.

$$\frac{0.25\times \frac{1}{4}}{16^{-1}}-\left(\pi -3\right)^{0}$$

Multiply 0.25 and \frac{1}{4} to get \frac{1}{16}.

$$\frac{\frac{1}{16}}{16^{-1}}-\left(\pi -3\right)^{0}$$

Calculate 16 to the power of -1 and get \frac{1}{16}.

$$\frac{\frac{1}{16}}{\frac{1}{16}}-\left(\pi -3\right)^{0}$$

Divide \frac{1}{16} by \frac{1}{16} to get 1.

$$1-\left(\pi -3\right)^{0}$$

Calculate \pi -3 to the power of 0 and get 1.

$$1-1$$

Subtract 1 from 1 to get 0.

$$0$$

Factor

$$0$$