Solve 0.07x+0.06y=398

$$0.07 x + 0.06 y = 398$$

Solve for x

$$x=\frac{39800-6y}{7}$$

Steps for Solving Linear Equation

Subtract 0.06y from both sides.

$$0.07x=398-0.06y$$

The equation is in standard form.

$$0.07x=-\frac{3y}{50}+398$$

Divide both sides of the equation by 0.07, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.07x}{0.07}=\frac{-\frac{3y}{50}+398}{0.07}$$

Dividing by 0.07 undoes the multiplication by 0.07.

$$x=\frac{-\frac{3y}{50}+398}{0.07}$$

Divide 398-\frac{3y}{50} by 0.07 by multiplying 398-\frac{3y}{50} by the reciprocal of 0.07.

$$x=\frac{39800-6y}{7}$$

Solve for y

$$y=-\frac{7x}{6}+\frac{19900}{3}$$

Steps for Solving Linear Equation

Subtract 0.07x from both sides.

$$0.06y=398-0.07x$$

The equation is in standard form.

$$0.06y=-\frac{7x}{100}+398$$

Divide both sides of the equation by 0.06, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.06y}{0.06}=\frac{-\frac{7x}{100}+398}{0.06}$$

Dividing by 0.06 undoes the multiplication by 0.06.

$$y=\frac{-\frac{7x}{100}+398}{0.06}$$

Divide 398-\frac{7x}{100} by 0.06 by multiplying 398-\frac{7x}{100} by the reciprocal of 0.06.

$$y=-\frac{7x}{6}+\frac{19900}{3}$$