Solve 0-65/3+(+13/4)-(-2/3)-(+1/4)=

$$0- \frac{ 65 }{ 3 } +(+ \frac{ 13 }{ 4 } )-(- \frac{ 2 }{ 3 } )-(+ \frac{ 1 }{ 4 } )=$$

Evaluate

$$-18$$

Solution Steps

Subtract \frac{65}{3} from 0 to get -\frac{65}{3}.

$$-\frac{65}{3}+\frac{13}{4}-\left(-\frac{2}{3}\right)-\frac{1}{4}$$

Least common multiple of 3 and 4 is 12. Convert -\frac{65}{3} and \frac{13}{4} to fractions with denominator 12.

$$-\frac{260}{12}+\frac{39}{12}-\left(-\frac{2}{3}\right)-\frac{1}{4}$$

Since -\frac{260}{12} and \frac{39}{12} have the same denominator, add them by adding their numerators.

$$\frac{-260+39}{12}-\left(-\frac{2}{3}\right)-\frac{1}{4}$$

Add -260 and 39 to get -221.

$$-\frac{221}{12}-\left(-\frac{2}{3}\right)-\frac{1}{4}$$

The opposite of -\frac{2}{3} is \frac{2}{3}.

$$-\frac{221}{12}+\frac{2}{3}-\frac{1}{4}$$

Least common multiple of 12 and 3 is 12. Convert -\frac{221}{12} and \frac{2}{3} to fractions with denominator 12.

$$-\frac{221}{12}+\frac{8}{12}-\frac{1}{4}$$

Since -\frac{221}{12} and \frac{8}{12} have the same denominator, add them by adding their numerators.

$$\frac{-221+8}{12}-\frac{1}{4}$$

Add -221 and 8 to get -213.

$$\frac{-213}{12}-\frac{1}{4}$$

Reduce the fraction \frac{-213}{12} to lowest terms by extracting and canceling out 3.

$$-\frac{71}{4}-\frac{1}{4}$$

Since -\frac{71}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-71-1}{4}$$

Subtract 1 from -71 to get -72.

$$\frac{-72}{4}$$

Divide -72 by 4 to get -18.

$$-18$$

Factor

$$-18$$