Solve 0=9-2sqrt{2x+4}

$$0=9-2 \sqrt{ 2x+4 }$$

Solve for x

$$x = \frac{65}{8} = 8\frac{1}{8} = 8.125$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$9-2\sqrt{2x+4}=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$-2\sqrt{2x+4}=-9$$

Divide both sides by -2.

$$\sqrt{2x+4}=\frac{-9}{-2}$$

Fraction \frac{-9}{-2} can be simplified to \frac{9}{2} by removing the negative sign from both the numerator and the denominator.

$$\sqrt{2x+4}=\frac{9}{2}$$

Square both sides of the equation.

$$2x+4=\frac{81}{4}$$

Subtract 4 from both sides of the equation.

$$2x+4-4=\frac{81}{4}-4$$

Subtracting 4 from itself leaves 0.

$$2x=\frac{81}{4}-4$$

Subtract 4 from \frac{81}{4}.

$$2x=\frac{65}{4}$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{\frac{65}{4}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{\frac{65}{4}}{2}$$

Divide \frac{65}{4} by 2.

$$x=\frac{65}{8}$$