Solve 0=1/9left(0+3right)left(0+4right)(0-2)

$$0= \frac{ 1 }{ 9 } \left( 0+3 \right) \left( 0+4 \right) (0-2)$$

Verify

Solution Steps

Add 0 and 3 to get 3.

$$0=\frac{1}{9}\times 3\left(0+4\right)\left(0-2\right)$$

Multiply \frac{1}{9} and 3 to get \frac{3}{9}.

$$0=\frac{3}{9}\left(0+4\right)\left(0-2\right)$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$0=\frac{1}{3}\left(0+4\right)\left(0-2\right)$$

Add 0 and 4 to get 4.

$$0=\frac{1}{3}\times 4\left(0-2\right)$$

Multiply \frac{1}{3} and 4 to get \frac{4}{3}.

$$0=\frac{4}{3}\left(0-2\right)$$

Subtract 2 from 0 to get -2.

$$0=\frac{4}{3}\left(-2\right)$$

Express \frac{4}{3}\left(-2\right) as a single fraction.

$$0=\frac{4\left(-2\right)}{3}$$

Multiply 4 and -2 to get -8.

$$0=\frac{-8}{3}$$

Fraction \frac{-8}{3} can be rewritten as -\frac{8}{3} by extracting the negative sign.

$$0=-\frac{8}{3}$$

Compare 0 and -\frac{8}{3}.

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