Solve 0,5x-2,5-5x-5-5x-0

$$0,5 x - 2,5 - 5 x - 5 - 5 x - 0$$

Evaluate

$$\frac{-19x-15}{2}$$

Solution Steps

Combine 0,5x and -5x to get -4,5x.

$$-4,5x-2,5-5-5x-0$$

Subtract 5 from -2,5 to get -7,5.

$$-4,5x-7,5-5x-0$$

Combine -4,5x and -5x to get -9,5x.

$$-9,5x-7,5-0$$

Multiply -1 and 0 to get 0.

$$-9,5x-7,5+0$$

Add -7,5 and 0 to get -7,5.

$$-9,5x-7,5$$

Differentiate w.r.t. x

$$-9,5$$

Steps Using Derivative Rule for Sum

Combine 0,5x and -5x to get -4,5x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-4,5x-2,5-5-5x-0)$$

Subtract 5 from -2,5 to get -7,5.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-4,5x-7,5-5x-0)$$

Combine -4,5x and -5x to get -9,5x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-9,5x-7,5-0)$$

Multiply -1 and 0 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-9,5x-7,5+0)$$

Add -7,5 and 0 to get -7,5.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-9,5x-7,5)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-9,5x^{1-1}$$

Subtract 1 from 1.

$$-9,5x^{0}$$

For any term t except 0, t^{0}=1.

$$-9,5$$