Solve for x
x = -\frac{33}{14} = -2\frac{5}{14} \approx -2.357142857
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0+14x+33=0
Anything times zero gives zero.
33+14x=0
Add 0 and 33 to get 33.
14x=-33
Subtract 33 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-33}{14}
Divide both sides by 14.
x=-\frac{33}{14}
Fraction \frac{-33}{14} can be rewritten as -\frac{33}{14} by extracting the negative sign.
x ^ 2 +14x +33 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -14 rs = 33
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -7 - u s = -7 + u
Two numbers r and s sum up to -14 exactly when the average of the two numbers is \frac{1}{2}*-14 = -7. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-7 - u) (-7 + u) = 33
To solve for unknown quantity u, substitute these in the product equation rs = 33
49 - u^2 = 33
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 33-49 = -16
Simplify the expression by subtracting 49 on both sides
u^2 = 16 u = \pm\sqrt{16} = \pm 4
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-7 - 4 = -11 s = -7 + 4 = -3
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
Examples
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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