Solve 0^circ-|-3|-sqrt{27}+(pi-3)^0

$$0 ^ { \circ } - | - 3 | - \sqrt { 27 } + ( \pi - 3 ) ^ { 0 }$$

Evaluate

$$-3\sqrt{3}-2\approx -7.196152423$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$0-3-\sqrt{27}+\left(\pi -3\right)^{0}$$

Subtract 3 from 0 to get -3.

$$-3-\sqrt{27}+\left(\pi -3\right)^{0}$$

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$-3-3\sqrt{3}+\left(\pi -3\right)^{0}$$

Calculate \pi -3 to the power of 0 and get 1.

$$-3-3\sqrt{3}+1$$

Add -3 and 1 to get -2.

$$-2-3\sqrt{3}$$