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x^{4}-6x^{2}+5=0
Swap sides so that all variable terms are on the left hand side.
t^{2}-6t+5=0
Substitute t for x^{2}.
t=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\times 1\times 5}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -6 for b, and 5 for c in the quadratic formula.
t=\frac{6±4}{2}
Do the calculations.
t=5 t=1
Solve the equation t=\frac{6±4}{2} when ± is plus and when ± is minus.
x=\sqrt{5} x=-\sqrt{5} x=1 x=-1
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.