Solve for x
x=\frac{3\left(y+1\right)}{4}
Solve for y
y=\frac{4x}{3}-1
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3y+3-4x=0
Swap sides so that all variable terms are on the left hand side.
3-4x=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
-4x=-3y-3
Subtract 3 from both sides.
\frac{-4x}{-4}=\frac{-3y-3}{-4}
Divide both sides by -4.
x=\frac{-3y-3}{-4}
Dividing by -4 undoes the multiplication by -4.
x=\frac{3y+3}{4}
Divide -3y-3 by -4.
3y+3-4x=0
Swap sides so that all variable terms are on the left hand side.
3y-4x=-3
Subtract 3 from both sides. Anything subtracted from zero gives its negation.
3y=-3+4x
Add 4x to both sides.
3y=4x-3
The equation is in standard form.
\frac{3y}{3}=\frac{4x-3}{3}
Divide both sides by 3.
y=\frac{4x-3}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{4x}{3}-1
Divide -3+4x by 3.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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Linear equation
y = 3x + 4
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Matrix
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}