Solve 0=(-3(u+3)^2/8+1,5)+(3/8u^2+1,5)

$$0 = ( - \frac { 3 ( u + 3 ) ^ { 2 } } { 8 } + 1,5 ) + ( \frac { 3 } { 8 } u ^ { 2 } + 1,5 )$$

Solve for u

$$u=-\frac{1}{6}\approx -0,166666667$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8.

$$0=-3\left(u+3\right)^{2}+12+3u^{2}+12$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(u+3\right)^{2}.

$$0=-3\left(u^{2}+6u+9\right)+12+3u^{2}+12$$

Use the distributive property to multiply -3 by u^{2}+6u+9.

$$0=-3u^{2}-18u-27+12+3u^{2}+12$$

Add -27 and 12 to get -15.

$$0=-3u^{2}-18u-15+3u^{2}+12$$

Combine -3u^{2} and 3u^{2} to get 0.

$$0=-18u-15+12$$

Add -15 and 12 to get -3.

$$0=-18u-3$$

Swap sides so that all variable terms are on the left hand side.

$$-18u-3=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$-18u=3$$

Divide both sides by -18.

$$u=\frac{3}{-18}$$

Reduce the fraction \frac{3}{-18} to lowest terms by extracting and canceling out 3.

$$u=-\frac{1}{6}$$