Solve 0=sqrt{6r-5*3}

$$0 = \sqrt { 6 r - 5 \cdot 3 }$$

Solve for r

$$r = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Steps for Solving Radical Equations

Multiply 5 and 3 to get 15.

$$0=\sqrt{6r-15}$$

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{6r-15}=0$$

Square both sides of the equation.

$$6r-15=0$$

Add 15 to both sides of the equation.

$$6r-15-\left(-15\right)=-\left(-15\right)$$

Subtracting -15 from itself leaves 0.

$$6r=-\left(-15\right)$$

Subtract -15 from 0.

$$6r=15$$

Divide both sides by 6.

$$\frac{6r}{6}=\frac{15}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$r=\frac{15}{6}$$

Reduce the fraction \frac{15}{6} to lowest terms by extracting and canceling out 3.

$$r=\frac{5}{2}$$