Solve 0=p3-3p-1

$$0 = p3-3p-1$$

Solve for p

$$p=\frac{p_{3}-1}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$p_{3}-3p-1=0$$

Subtract p_{3} from both sides. Anything subtracted from zero gives its negation.

$$-3p-1=-p_{3}$$

Add 1 to both sides.

$$-3p=-p_{3}+1$$

The equation is in standard form.

$$-3p=1-p_{3}$$

Divide both sides by -3.

$$\frac{-3p}{-3}=\frac{1-p_{3}}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$p=\frac{1-p_{3}}{-3}$$

Divide -p_{3}+1 by -3.

$$p=\frac{p_{3}-1}{3}$$

Solve for p_3

$$p_{3}=3p+1$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$p_{3}-3p-1=0$$

Add 3p to both sides. Anything plus zero gives itself.

$$p_{3}-1=3p$$

Add 1 to both sides.

$$p_{3}=3p+1$$