Solve 0/frac{sqrt{36}}{sqrt{1}}=sqrt{36/81}=0/9=

$$0 / \frac { \sqrt { 36 } } { \sqrt { 1 } } = \sqrt { \frac { 36 } { 81 } } = \frac { 0 } { 9 } =$$

Verify

Solution Steps

Divide 0 by \frac{\sqrt{36}}{\sqrt{1}} by multiplying 0 by the reciprocal of \frac{\sqrt{36}}{\sqrt{1}}.

$$\frac{0\sqrt{1}}{\sqrt{36}}=\sqrt{\frac{36}{81}}\text{ and }\sqrt{\frac{36}{81}}=\frac{0}{9}$$

Calculate the square root of 1 and get 1.

$$\frac{0\times 1}{\sqrt{36}}=\sqrt{\frac{36}{81}}\text{ and }\sqrt{\frac{36}{81}}=\frac{0}{9}$$

Multiply 0 and 1 to get 0.

$$\frac{0}{\sqrt{36}}=\sqrt{\frac{36}{81}}\text{ and }\sqrt{\frac{36}{81}}=\frac{0}{9}$$

Calculate the square root of 36 and get 6.

$$\frac{0}{6}=\sqrt{\frac{36}{81}}\text{ and }\sqrt{\frac{36}{81}}=\frac{0}{9}$$

Zero divided by any non-zero number gives zero.

$$0=\sqrt{\frac{36}{81}}\text{ and }\sqrt{\frac{36}{81}}=\frac{0}{9}$$

Reduce the fraction \frac{36}{81} to lowest terms by extracting and canceling out 9.

$$0=\sqrt{\frac{4}{9}}\text{ and }\sqrt{\frac{36}{81}}=\frac{0}{9}$$

Rewrite the square root of the division \frac{4}{9} as the division of square roots \frac{\sqrt{4}}{\sqrt{9}}. Take the square root of both numerator and denominator.

$$0=\frac{2}{3}\text{ and }\sqrt{\frac{36}{81}}=\frac{0}{9}$$

Compare 0 and \frac{2}{3}.

$$\text{false}\text{ and }\sqrt{\frac{36}{81}}=\frac{0}{9}$$

Reduce the fraction \frac{36}{81} to lowest terms by extracting and canceling out 9.

$$\text{false}\text{ and }\sqrt{\frac{4}{9}}=\frac{0}{9}$$

Rewrite the square root of the division \frac{4}{9} as the division of square roots \frac{\sqrt{4}}{\sqrt{9}}. Take the square root of both numerator and denominator.

$$\text{false}\text{ and }\frac{2}{3}=\frac{0}{9}$$

Zero divided by any non-zero number gives zero.

$$\text{false}\text{ and }\frac{2}{3}=0$$

Compare \frac{2}{3} and 0.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$