Solve .15-28i=3ell+(4m)i

$$.15 - 28 i = 3 \ell + ( 4 m ) i$$

Solve for m

$$m=\frac{3iℓ}{4}+\left(-7-0.0375i\right)$$

Steps for Solving Linear Equation

Multiply 4 and i to get 4i.

$$0.15-28i=3ℓ+4im$$

Swap sides so that all variable terms are on the left hand side.

$$3ℓ+4im=0.15-28i$$

Subtract 3ℓ from both sides.

$$4im=0.15-28i-3ℓ$$

Divide both sides by 4i.

$$\frac{4im}{4i}=\frac{0.15-28i-3ℓ}{4i}$$

Dividing by 4i undoes the multiplication by 4i.

$$m=\frac{0.15-28i-3ℓ}{4i}$$

Divide 0.15-28i-3ℓ by 4i.

$$m=\frac{3iℓ}{4}+\left(-7-\frac{3}{80}i\right)$$

Solve for ℓ

$$ℓ=-\frac{4im}{3}+\left(0.05-\frac{28}{3}i\right)$$

Steps for Solving Linear Equation

Multiply 4 and i to get 4i.

$$0.15-28i=3ℓ+4im$$

Swap sides so that all variable terms are on the left hand side.

$$3ℓ+4im=0.15-28i$$

Subtract 4im from both sides.

$$3ℓ=0.15-28i-4im$$

Divide both sides by 3.

$$\frac{3ℓ}{3}=\frac{0.15-28i-4im}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$ℓ=\frac{0.15-28i-4im}{3}$$

Divide 0.15-28i-4im by 3.

$$ℓ=-\frac{4im}{3}+\left(\frac{1}{20}-\frac{28}{3}i\right)$$