Solve -9div3+(1/2-2/3)*12--3^2=

$$-9 \div 3+( \frac{ 1 }{ 2 } - \frac{ 2 }{ 3 } ) \times 12- { -3 }^{ 2 } =$$

Evaluate

$$-14$$

Solution Steps

Divide -9 by 3 to get -3.

$$-3+\left(\frac{1}{2}-\frac{2}{3}\right)\times 12-\left(-3\right)^{2}$$

Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{2}{3} to fractions with denominator 6.

$$-3+\left(\frac{3}{6}-\frac{4}{6}\right)\times 12-\left(-3\right)^{2}$$

Since \frac{3}{6} and \frac{4}{6} have the same denominator, subtract them by subtracting their numerators.

$$-3+\frac{3-4}{6}\times 12-\left(-3\right)^{2}$$

Subtract 4 from 3 to get -1.

$$-3-\frac{1}{6}\times 12-\left(-3\right)^{2}$$

Express -\frac{1}{6}\times 12 as a single fraction.

$$-3+\frac{-12}{6}-\left(-3\right)^{2}$$

Divide -12 by 6 to get -2.

$$-3-2-\left(-3\right)^{2}$$

Subtract 2 from -3 to get -5.

$$-5-\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$-5-9$$

Subtract 9 from -5 to get -14.

$$-14$$

Factor

$$-14$$