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-6x=3\sqrt{3}
Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.
\frac{-6x}{-6}=\frac{3\sqrt{3}}{-6}
Divide both sides by -6.
x=\frac{3\sqrt{3}}{-6}
Dividing by -6 undoes the multiplication by -6.
x=-\frac{\sqrt{3}}{2}
Divide 3\sqrt{3} by -6.