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-c^{2}-36c+576=0
Divide both sides by 64.
a+b=-36 ab=-576=-576
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -c^{2}+ac+bc+576. To find a and b, set up a system to be solved.
1,-576 2,-288 3,-192 4,-144 6,-96 8,-72 9,-64 12,-48 16,-36 18,-32 24,-24
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -576.
1-576=-575 2-288=-286 3-192=-189 4-144=-140 6-96=-90 8-72=-64 9-64=-55 12-48=-36 16-36=-20 18-32=-14 24-24=0
Calculate the sum for each pair.
a=12 b=-48
The solution is the pair that gives sum -36.
\left(-c^{2}+12c\right)+\left(-48c+576\right)
Rewrite -c^{2}-36c+576 as \left(-c^{2}+12c\right)+\left(-48c+576\right).
c\left(-c+12\right)+48\left(-c+12\right)
Factor out c in the first and 48 in the second group.
\left(-c+12\right)\left(c+48\right)
Factor out common term -c+12 by using distributive property.
c=12 c=-48
To find equation solutions, solve -c+12=0 and c+48=0.
-64c^{2}-2304c+36864=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
c=\frac{-\left(-2304\right)±\sqrt{\left(-2304\right)^{2}-4\left(-64\right)\times 36864}}{2\left(-64\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -64 for a, -2304 for b, and 36864 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
c=\frac{-\left(-2304\right)±\sqrt{5308416-4\left(-64\right)\times 36864}}{2\left(-64\right)}
Square -2304.
c=\frac{-\left(-2304\right)±\sqrt{5308416+256\times 36864}}{2\left(-64\right)}
Multiply -4 times -64.
c=\frac{-\left(-2304\right)±\sqrt{5308416+9437184}}{2\left(-64\right)}
Multiply 256 times 36864.
c=\frac{-\left(-2304\right)±\sqrt{14745600}}{2\left(-64\right)}
Add 5308416 to 9437184.
c=\frac{-\left(-2304\right)±3840}{2\left(-64\right)}
Take the square root of 14745600.
c=\frac{2304±3840}{2\left(-64\right)}
The opposite of -2304 is 2304.
c=\frac{2304±3840}{-128}
Multiply 2 times -64.
c=\frac{6144}{-128}
Now solve the equation c=\frac{2304±3840}{-128} when ± is plus. Add 2304 to 3840.
c=-48
Divide 6144 by -128.
c=-\frac{1536}{-128}
Now solve the equation c=\frac{2304±3840}{-128} when ± is minus. Subtract 3840 from 2304.
c=12
Divide -1536 by -128.
c=-48 c=12
The equation is now solved.
-64c^{2}-2304c+36864=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
-64c^{2}-2304c+36864-36864=-36864
Subtract 36864 from both sides of the equation.
-64c^{2}-2304c=-36864
Subtracting 36864 from itself leaves 0.
\frac{-64c^{2}-2304c}{-64}=-\frac{36864}{-64}
Divide both sides by -64.
c^{2}+\left(-\frac{2304}{-64}\right)c=-\frac{36864}{-64}
Dividing by -64 undoes the multiplication by -64.
c^{2}+36c=-\frac{36864}{-64}
Divide -2304 by -64.
c^{2}+36c=576
Divide -36864 by -64.
c^{2}+36c+18^{2}=576+18^{2}
Divide 36, the coefficient of the x term, by 2 to get 18. Then add the square of 18 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
c^{2}+36c+324=576+324
Square 18.
c^{2}+36c+324=900
Add 576 to 324.
\left(c+18\right)^{2}=900
Factor c^{2}+36c+324. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(c+18\right)^{2}}=\sqrt{900}
Take the square root of both sides of the equation.
c+18=30 c+18=-30
Simplify.
c=12 c=-48
Subtract 18 from both sides of the equation.