Solve -6left(+0.20right)^4-3left(+0.20right)^3+6left(+0.20right)^2

$$-6 { \left(+0.20 \right) }^{ 4 } -3 { \left(+0.20 \right) }^{ 3 } +6 { \left(+0.20 \right) }^{ 2 }$$

Evaluate

$$0.2064$$

Solution Steps

Calculate 0.2 to the power of 4 and get 0.0016.

$$-6\times 0.0016-3\times 0.2^{3}+6\times 0.2^{2}$$

Multiply -6 and 0.0016 to get -0.0096.

$$-0.0096-3\times 0.2^{3}+6\times 0.2^{2}$$

Calculate 0.2 to the power of 3 and get 0.008.

$$-0.0096-3\times 0.008+6\times 0.2^{2}$$

Multiply 3 and 0.008 to get 0.024.

$$-0.0096-0.024+6\times 0.2^{2}$$

Subtract 0.024 from -0.0096 to get -0.0336.

$$-0.0336+6\times 0.2^{2}$$

Calculate 0.2 to the power of 2 and get 0.04.

$$-0.0336+6\times 0.04$$

Multiply 6 and 0.04 to get 0.24.

$$-0.0336+0.24$$

Add -0.0336 and 0.24 to get 0.2064.

$$0.2064$$

Factor

$$\frac{3 \cdot 43}{5 ^ {4}} = 0.2064$$