Solve for B
\left\{\begin{matrix}\\B=4\left(1-2x\right)x^{2}\text{, }&\text{unconditionally}\\B\in \mathrm{R}\text{, }&x=0\end{matrix}\right.
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\left(-4x^{2}\right)B=32x^{5}-16x^{4}
The equation is in standard form.
\frac{\left(-4x^{2}\right)B}{-4x^{2}}=\frac{16\left(2x-1\right)x^{4}}{-4x^{2}}
Divide both sides by -4x^{2}.
B=\frac{16\left(2x-1\right)x^{4}}{-4x^{2}}
Dividing by -4x^{2} undoes the multiplication by -4x^{2}.
B=-4\left(2x-1\right)x^{2}
Divide 16\left(-1+2x\right)x^{4} by -4x^{2}.
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