Solve -3x-1/5<x+1

$$-3x- \frac{ 1 }{ 5 } < x+1$$

Solve for x

$$x>-\frac{3}{10}$$

Solution Steps

Subtract x from both sides.

$$-3x-\frac{1}{5}-x<1$$

Combine -3x and -x to get -4x.

$$-4x-\frac{1}{5}<1$$

Add \frac{1}{5} to both sides.

$$-4x<1+\frac{1}{5}$$

Convert 1 to fraction \frac{5}{5}.

$$-4x<\frac{5}{5}+\frac{1}{5}$$

Since \frac{5}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.

$$-4x<\frac{5+1}{5}$$

Add 5 and 1 to get 6.

$$-4x<\frac{6}{5}$$

Divide both sides by -4. Since -4 is negative, the inequality direction is changed.

$$x>\frac{\frac{6}{5}}{-4}$$

Express \frac{\frac{6}{5}}{-4} as a single fraction.

$$x>\frac{6}{5\left(-4\right)}$$

Multiply 5 and -4 to get -20.

$$x>\frac{6}{-20}$$

Reduce the fraction \frac{6}{-20} to lowest terms by extracting and canceling out 2.

$$x>-\frac{3}{10}$$