Solve for x
x<\frac{20}{3}
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-30x>300-500
Subtract 500 from both sides.
-30x>-200
Subtract 500 from 300 to get -200.
x<\frac{-200}{-30}
Divide both sides by -30. Since -30 is negative, the inequality direction is changed.
x<\frac{20}{3}
Reduce the fraction \frac{-200}{-30} to lowest terms by extracting and canceling out -10.
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