Solve -3(6x-5)-9(8-10x)+16-26(1-x)=0

$$-3(6x-5)-9(8-10x)+16-26(1-x)=0$$

Solve for x

$$x=\frac{67}{98}\approx 0.683673469$$

Steps for Solving Linear Equation

Use the distributive property to multiply -3 by 6x-5.

$$-18x+15-9\left(8-10x\right)+16-26\left(1-x\right)=0$$

Use the distributive property to multiply -9 by 8-10x.

$$-18x+15-72+90x+16-26\left(1-x\right)=0$$

Subtract 72 from 15 to get -57.

$$-18x-57+90x+16-26\left(1-x\right)=0$$

Combine -18x and 90x to get 72x.

$$72x-57+16-26\left(1-x\right)=0$$

Add -57 and 16 to get -41.

$$72x-41-26\left(1-x\right)=0$$

Use the distributive property to multiply -26 by 1-x.

$$72x-41-26+26x=0$$

Subtract 26 from -41 to get -67.

$$72x-67+26x=0$$

Combine 72x and 26x to get 98x.

$$98x-67=0$$

Add 67 to both sides. Anything plus zero gives itself.

$$98x=67$$

Divide both sides by 98.

$$x=\frac{67}{98}$$