Solve -3(4x)+-3(2x)

$$-3(4x)+-3(2x)$$

Evaluate

$$-18x$$

Solution Steps

Multiply -3 and 4 to get -12. Multiply -3 and 2 to get -6.

$$-12x-6x$$

Combine -12x and -6x to get -18x.

$$-18x$$

Differentiate w.r.t. x

$$-18$$

Steps Using Definition of a Derivative

Multiply -3 and 4 to get -12. Multiply -3 and 2 to get -6.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-12x-6x)$$

Combine -12x and -6x to get -18x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-18x)$$

The derivative of ax^{n} is nax^{n-1}.

$$-18x^{1-1}$$

Subtract 1 from 1.

$$-18x^{0}$$

For any term t except 0, t^{0}=1.

$$-18$$