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-3x^{2}+6x+4=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-6±\sqrt{6^{2}-4\left(-3\right)\times 4}}{2\left(-3\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-6±\sqrt{36-4\left(-3\right)\times 4}}{2\left(-3\right)}
Square 6.
x=\frac{-6±\sqrt{36+12\times 4}}{2\left(-3\right)}
Multiply -4 times -3.
x=\frac{-6±\sqrt{36+48}}{2\left(-3\right)}
Multiply 12 times 4.
x=\frac{-6±\sqrt{84}}{2\left(-3\right)}
Add 36 to 48.
x=\frac{-6±2\sqrt{21}}{2\left(-3\right)}
Take the square root of 84.
x=\frac{-6±2\sqrt{21}}{-6}
Multiply 2 times -3.
x=\frac{2\sqrt{21}-6}{-6}
Now solve the equation x=\frac{-6±2\sqrt{21}}{-6} when ± is plus. Add -6 to 2\sqrt{21}.
x=-\frac{\sqrt{21}}{3}+1
Divide -6+2\sqrt{21} by -6.
x=\frac{-2\sqrt{21}-6}{-6}
Now solve the equation x=\frac{-6±2\sqrt{21}}{-6} when ± is minus. Subtract 2\sqrt{21} from -6.
x=\frac{\sqrt{21}}{3}+1
Divide -6-2\sqrt{21} by -6.
-3x^{2}+6x+4=-3\left(x-\left(-\frac{\sqrt{21}}{3}+1\right)\right)\left(x-\left(\frac{\sqrt{21}}{3}+1\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 1-\frac{\sqrt{21}}{3} for x_{1} and 1+\frac{\sqrt{21}}{3} for x_{2}.