Solve for x
x=-\frac{3y}{2}+12
Solve for y
y=-\frac{2x}{3}+8
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-2x=-24+3y
Add 3y to both sides.
-2x=3y-24
The equation is in standard form.
\frac{-2x}{-2}=\frac{3y-24}{-2}
Divide both sides by -2.
x=\frac{3y-24}{-2}
Dividing by -2 undoes the multiplication by -2.
x=-\frac{3y}{2}+12
Divide -24+3y by -2.
-3y=-24+2x
Add 2x to both sides.
-3y=2x-24
The equation is in standard form.
\frac{-3y}{-3}=\frac{2x-24}{-3}
Divide both sides by -3.
y=\frac{2x-24}{-3}
Dividing by -3 undoes the multiplication by -3.
y=-\frac{2x}{3}+8
Divide -24+2x by -3.
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