Solve for x
x=-\frac{3y}{2}+8
Solve for y
y=\frac{16-2x}{3}
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-2x+16=3y
Add 3y to both sides. Anything plus zero gives itself.
-2x=3y-16
Subtract 16 from both sides.
\frac{-2x}{-2}=\frac{3y-16}{-2}
Divide both sides by -2.
x=\frac{3y-16}{-2}
Dividing by -2 undoes the multiplication by -2.
x=-\frac{3y}{2}+8
Divide 3y-16 by -2.
-3y+16=2x
Add 2x to both sides. Anything plus zero gives itself.
-3y=2x-16
Subtract 16 from both sides.
\frac{-3y}{-3}=\frac{2x-16}{-3}
Divide both sides by -3.
y=\frac{2x-16}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{16-2x}{3}
Divide -16+2x by -3.
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Limits
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