Solve -2x^6+5x^5+9x^2+2divx^4

$$-2 { x }^{ 6 } +5 { x }^{ 5 } +9 { x }^{ 2 } +2 \div { x }^{ 4 }$$

Evaluate

$$-2x^{6}+5x^{5}+9x^{2}+\frac{2}{x^{4}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply -2x^{6}+5x^{5}+9x^{2} times \frac{x^{4}}{x^{4}}.

$$\frac{\left(-2x^{6}+5x^{5}+9x^{2}\right)x^{4}}{x^{4}}+\frac{2}{x^{4}}$$

Since \frac{\left(-2x^{6}+5x^{5}+9x^{2}\right)x^{4}}{x^{4}} and \frac{2}{x^{4}} have the same denominator, add them by adding their numerators.

$$\frac{\left(-2x^{6}+5x^{5}+9x^{2}\right)x^{4}+2}{x^{4}}$$

Do the multiplications in \left(-2x^{6}+5x^{5}+9x^{2}\right)x^{4}+2.

$$\frac{-2x^{10}+5x^{9}+9x^{6}+2}{x^{4}}$$

Factor

$$-\frac{2x^{10}-5x^{9}-9x^{6}-2}{x^{4}}$$