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x\left(-2x+8\right)=0
Factor out x.
x=0 x=4
To find equation solutions, solve x=0 and -2x+8=0.
-2x^{2}+8x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-8±\sqrt{8^{2}}}{2\left(-2\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -2 for a, 8 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-8±8}{2\left(-2\right)}
Take the square root of 8^{2}.
x=\frac{-8±8}{-4}
Multiply 2 times -2.
x=\frac{0}{-4}
Now solve the equation x=\frac{-8±8}{-4} when ± is plus. Add -8 to 8.
x=0
Divide 0 by -4.
x=-\frac{16}{-4}
Now solve the equation x=\frac{-8±8}{-4} when ± is minus. Subtract 8 from -8.
x=4
Divide -16 by -4.
x=0 x=4
The equation is now solved.
-2x^{2}+8x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-2x^{2}+8x}{-2}=\frac{0}{-2}
Divide both sides by -2.
x^{2}+\frac{8}{-2}x=\frac{0}{-2}
Dividing by -2 undoes the multiplication by -2.
x^{2}-4x=\frac{0}{-2}
Divide 8 by -2.
x^{2}-4x=0
Divide 0 by -2.
x^{2}-4x+\left(-2\right)^{2}=\left(-2\right)^{2}
Divide -4, the coefficient of the x term, by 2 to get -2. Then add the square of -2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-4x+4=4
Square -2.
\left(x-2\right)^{2}=4
Factor x^{2}-4x+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-2\right)^{2}}=\sqrt{4}
Take the square root of both sides of the equation.
x-2=2 x-2=-2
Simplify.
x=4 x=0
Add 2 to both sides of the equation.