Solve -15x+10y+38=0

$$-15x+10y+38 = 0$$

Solve for x

$$x=\frac{2y}{3}+\frac{38}{15}$$

Steps for Solving Linear Equation

Subtract 10y from both sides. Anything subtracted from zero gives its negation.

$$-15x+38=-10y$$

Subtract 38 from both sides.

$$-15x=-10y-38$$

Divide both sides by -15.

$$\frac{-15x}{-15}=\frac{-10y-38}{-15}$$

Dividing by -15 undoes the multiplication by -15.

$$x=\frac{-10y-38}{-15}$$

Divide -10y-38 by -15.

$$x=\frac{2y}{3}+\frac{38}{15}$$

Solve for y

$$y=\frac{3x}{2}-\frac{19}{5}$$

Steps for Solving Linear Equation

Add 15x to both sides. Anything plus zero gives itself.

$$10y+38=15x$$

Subtract 38 from both sides.

$$10y=15x-38$$

Divide both sides by 10.

$$\frac{10y}{10}=\frac{15x-38}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$y=\frac{15x-38}{10}$$

Divide 15x-38 by 10.

$$y=\frac{3x}{2}-\frac{19}{5}$$