Solve -12x-16y+56=0

$$-12x-16y+56=0$$

Solve for x

$$x=\frac{14-4y}{3}$$

Steps for Solving Linear Equation

Add 16y to both sides. Anything plus zero gives itself.

$$-12x+56=16y$$

Subtract 56 from both sides.

$$-12x=16y-56$$

Divide both sides by -12.

$$\frac{-12x}{-12}=\frac{16y-56}{-12}$$

Dividing by -12 undoes the multiplication by -12.

$$x=\frac{16y-56}{-12}$$

Divide 16y-56 by -12.

$$x=\frac{14-4y}{3}$$

Solve for y

$$y=-\frac{3x}{4}+\frac{7}{2}$$

Steps for Solving Linear Equation

Add 12x to both sides. Anything plus zero gives itself.

$$-16y+56=12x$$

Subtract 56 from both sides.

$$-16y=12x-56$$

Divide both sides by -16.

$$\frac{-16y}{-16}=\frac{12x-56}{-16}$$

Dividing by -16 undoes the multiplication by -16.

$$y=\frac{12x-56}{-16}$$

Divide 12x-56 by -16.

$$y=-\frac{3x}{4}+\frac{7}{2}$$