Solve ---4-7---3+-24/6+-5+-4*2

$$---4-7---3+ \frac{ -24 }{ 6 } +-5+-4 \cdot 2$$

Evaluate

$$-31$$

Solution Steps

The opposite of -4 is 4.

$$-4-7-\left(-\left(-3\right)\right)+\frac{-24}{6}-5-4\times 2$$

Subtract 7 from -4 to get -11.

$$-11-\left(-\left(-3\right)\right)+\frac{-24}{6}-5-4\times 2$$

The opposite of -3 is 3.

$$-11-3+\frac{-24}{6}-5-4\times 2$$

Subtract 3 from -11 to get -14.

$$-14+\frac{-24}{6}-5-4\times 2$$

Divide -24 by 6 to get -4.

$$-14-4-5-4\times 2$$

Subtract 4 from -14 to get -18.

$$-18-5-4\times 2$$

Subtract 5 from -18 to get -23.

$$-23-4\times 2$$

Multiply -4 and 2 to get -8.

$$-23-8$$

Subtract 8 from -23 to get -31.

$$-31$$

Factor

$$-31$$