Solve -y+1=0text{and}3x+2y-12=0

$$- y + 1 = 0 \text { and } 3 x + 2 y - 12 = 0$$

Solve for y, x

$$x = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333$$

$$y=1$$

Solution Steps

Consider the first equation. Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-y=-1$$

Divide both sides by -1.

$$y=\frac{-1}{-1}$$

Divide -1 by -1 to get 1.

$$y=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$3x+2\times 1-12=0$$

Multiply 2 and 1 to get 2.

$$3x+2-12=0$$

Subtract 12 from 2 to get -10.

$$3x-10=0$$

Add 10 to both sides. Anything plus zero gives itself.

$$3x=10$$

Divide both sides by 3.

$$x=\frac{10}{3}$$

The system is now solved.

$$y=1 x=\frac{10}{3}$$