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-x^{2}-48x+380=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-48\right)±\sqrt{\left(-48\right)^{2}-4\left(-1\right)\times 380}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, -48 for b, and 380 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-48\right)±\sqrt{2304-4\left(-1\right)\times 380}}{2\left(-1\right)}
Square -48.
x=\frac{-\left(-48\right)±\sqrt{2304+4\times 380}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{-\left(-48\right)±\sqrt{2304+1520}}{2\left(-1\right)}
Multiply 4 times 380.
x=\frac{-\left(-48\right)±\sqrt{3824}}{2\left(-1\right)}
Add 2304 to 1520.
x=\frac{-\left(-48\right)±4\sqrt{239}}{2\left(-1\right)}
Take the square root of 3824.
x=\frac{48±4\sqrt{239}}{2\left(-1\right)}
The opposite of -48 is 48.
x=\frac{48±4\sqrt{239}}{-2}
Multiply 2 times -1.
x=\frac{4\sqrt{239}+48}{-2}
Now solve the equation x=\frac{48±4\sqrt{239}}{-2} when ± is plus. Add 48 to 4\sqrt{239}.
x=-2\sqrt{239}-24
Divide 48+4\sqrt{239} by -2.
x=\frac{48-4\sqrt{239}}{-2}
Now solve the equation x=\frac{48±4\sqrt{239}}{-2} when ± is minus. Subtract 4\sqrt{239} from 48.
x=2\sqrt{239}-24
Divide 48-4\sqrt{239} by -2.
x=-2\sqrt{239}-24 x=2\sqrt{239}-24
The equation is now solved.
-x^{2}-48x+380=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
-x^{2}-48x+380-380=-380
Subtract 380 from both sides of the equation.
-x^{2}-48x=-380
Subtracting 380 from itself leaves 0.
\frac{-x^{2}-48x}{-1}=-\frac{380}{-1}
Divide both sides by -1.
x^{2}+\left(-\frac{48}{-1}\right)x=-\frac{380}{-1}
Dividing by -1 undoes the multiplication by -1.
x^{2}+48x=-\frac{380}{-1}
Divide -48 by -1.
x^{2}+48x=380
Divide -380 by -1.
x^{2}+48x+24^{2}=380+24^{2}
Divide 48, the coefficient of the x term, by 2 to get 24. Then add the square of 24 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+48x+576=380+576
Square 24.
x^{2}+48x+576=956
Add 380 to 576.
\left(x+24\right)^{2}=956
Factor x^{2}+48x+576. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+24\right)^{2}}=\sqrt{956}
Take the square root of both sides of the equation.
x+24=2\sqrt{239} x+24=-2\sqrt{239}
Simplify.
x=2\sqrt{239}-24 x=-2\sqrt{239}-24
Subtract 24 from both sides of the equation.
x ^ 2 +48x -380 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -48 rs = -380
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -24 - u s = -24 + u
Two numbers r and s sum up to -48 exactly when the average of the two numbers is \frac{1}{2}*-48 = -24. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-24 - u) (-24 + u) = -380
To solve for unknown quantity u, substitute these in the product equation rs = -380
576 - u^2 = -380
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -380-576 = -956
Simplify the expression by subtracting 576 on both sides
u^2 = 956 u = \pm\sqrt{956} = \pm \sqrt{956}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-24 - \sqrt{956} = -54.919 s = -24 + \sqrt{956} = 6.919
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.